Verified Solution • 2025–26 Session moderate

QJEEM19Phe64d: JEE Main 2019 Physics - Class 12 JEEM19Phe64d Solution: A transformer consisting of 300 turns in the primary and 150…

A transformer consisting of 300 turns in the primary and 150 turns in the secondary gives output power of 2.2 kW. If the current in the secondary coil is 10A, then the input voltage and current in the primary coil are :

Multiple Choice Options

  • A 220 V and 20 A
  • B 220 V and 10A
  • C 440 V and 5A
  • D 440 V and 20 A

Step-by-Step Verified Solution

Given NP = 300, Ns = 150, P0 = 2200W

Is = 10 A
P0 = V0I0 ⇒\Rightarrow 2200 = V0 × 10 ⇒\Rightarrow V0 = 220 V

∵\because ViV0=NPNS⇒Vi=2×220=440 V{{{V_i}} \over {{V_0}}} = {{{N_P}} \over {{N_S}}} \Rightarrow {V_i} = 2 \times 220 = 440\,V

Also, P0 = ViIi
⇒Ii=2200440=5A\Rightarrow {I_i} = {{2200} \over {440}} = 5A

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