Verified Solution • 2025–26 Session moderate

QJEEM19Phe590: JEE Main 2019 Physics - Class 12 JEEM19Phe590 Solution: Two electric bulbs, rated at (25 W, 220 V) and (100 W, 220 V),…

Two electric bulbs, rated at (25 W, 220 V) and (100 W, 220 V), are connected in series across a 220 V voltage source. If the 25 W and 100 W bulbs draw powers P₁ and P₂ respectively, then :

Multiple Choice Options

A P1 = 4W, P2 = 16 W
B P1 = 16W, P2 = 4 W
C P1 = 9W, P2 = 16 W
D P1 = 16W, P2 = 9 W

Step-by-Step Verified Solution

R_{1} = \frac{220^{2}}{25}

R_{2} = \frac{220^{2}}{100}

L = \frac{220}{R_{1} + R_{2}}

P_{1} = i^{2} R_{1}

P_{2} = i^{2} (R_{2} = 4 W)

= \frac{220^{2}}{(\frac{220^{2}}{25} + \frac{220^{2}}{100})} \times \frac{220^{2}}{25}

= \frac{400}{25} = 16 W

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