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QJEEM19Phd6b9: JEE Main 2019 Physics - Class 12 JEEM19Phd6b9 Solution: Figure shows charge (q) versus voltage (V) graph for series and …

Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are : JEE Main 2019 (Online) 10th April Morning Slot Physics - Capacitor Question 110 English

Multiple Choice Options

  • A 40 μF and 10 μF
  • B 60 μF and 40 μF
  • C 20 μF and 30 μF
  • D 50 μF and 30 μF

Step-by-Step Verified Solution

As q = CV
Hence slope of graph will give capacitance. Slope will be more in parallel combination. Hence capacitance in parallel should be 50 μF and in series combination must be 8 μF. Only in option 40 μf and 10 μF.

Cparallel = 40 + 10 = 50 μF

Cseries = 40×1040+10=8μF

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