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QJEEM19Phd626: JEE Main 2019 Physics - Class 11 JEEM19Phd626 Solution: A mass of 10 kg is suspended vertically by a rope from the…

A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point. the rope deviated at an angle of 45o at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 ms−2

Multiple Choice Options

  • A 200 N
  • B 140 N
  • C 70 N
  • D 100 N

Step-by-Step Verified Solution

JEE Main 2019 (Online) 9th January Evening Slot Physics - Laws of Motion Question 104 English Explanation
tan 45o = Fmg

∴  F = mg

= 10 × 10

= 100 N

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