QJEEM19Phd48f: JEE Main 2019 Physics - Class 12 JEEM19Phd48f Solution: In a Young's double slit experiment, the path difference, at a…

Question

Verified Solution • 2025–26 Session moderate

In a Young's double slit experiment, the path difference, at a certain point on the screen, between two interfering waves is

\frac{1}{8}

th of wavelength. The ratio of the intensity at this point to that at the centre of a bright fringe is close to :

Accepted Answer

Δ

x

=

\frac{λ}{8}

Δ

ϕ

=

\frac{(2 π)}{λ} \frac{λ}{8} = \frac{π}{4}

I

=

I₀cos²

(\frac{π}{8})

\frac{I}{I_{0}} =

cos²

(\frac{π}{8})

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