QJEEM19Phcfe5: JEE Main 2019 Physics - Class 12 JEEM19Phcfe5 Solution: In an interference experiment the ratio of amplitudes of…

Question

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In an interference experiment the ratio of amplitudes of coherent waves is

{{{a_1}} \over {{a_2}}} = {1 \over 3}

. The ratio of maximum and minimum intensities of fringes will be :

Accepted Answer

{{{I_{\max }}} \over {{I_{\min }}}} = {{{{\left( {{a_1} + {a_2}} \right)}^2}} \over {{{\left( {{a_1} - {a_2}} \right)}^2}}} = {{{{\left( {1 + 3} \right)}^2}} \over {{{\left( {1 - 3} \right)}^2}}} = {{16} \over 4}

= 4

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