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QJEEM19Phce3a: JEE Main 2019 Physics - Class 12 JEEM19Phce3a Solution: The figure shows a Young's double slit experimental setup. It…

The figure shows a Young's double slit experimental setup. It is observed that when a thin transparent sheet of thickness t and refractive index μ is put in front of one of the slits, the central maximum gest shifted by a distance equal to n fringe widths. If the wavelength of light used is λ\lambda , t will be : JEE Main 2019 (Online) 9th April Morning Slot Physics - Wave Optics Question 106 English

Multiple Choice Options

  • A Dλa(μ−1){{D\lambda } \over {a\left( {\mu - 1} \right)}}
  • B 2nDλa(μ−1){{2nD\lambda } \over {a\left( {\mu - 1} \right)}}
  • C 2Dλa(μ−1){{2D\lambda } \over {a\left( {\mu - 1} \right)}}
  • D nλ(μ−1){{n\lambda } \over {\left( {\mu - 1} \right)}}

Step-by-Step Verified Solution

Path difference at central maxima Δ\Delta x = ( μ\mu – 1)t, whole pattern will shift by same amount which will be given by

(μ−1)tDd=nλDd;\left( {\mu - 1} \right)t{D \over d} = n{{\lambda D} \over d}; according to the question t=nλ(μ−1)t = {{n\lambda } \over {\left( {\mu - 1} \right)}}

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