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QJEEM19Phc36c: JEE Main 2019 Physics - Class 11 JEEM19Phc36c Solution: A particle of mass 20 g is released with an initial velocity 5…

A particle of mass 20 g is released with an initial velocity 5 m/s along the curve from the point A, as shown in the figure. The point A is at height h from point B. The particle slides along the frictionless surface. when the particle reaches point b, its angular momentum about O will be :
(Take g = 10 m/s2)

JEE Main 2019 (Online) 12th January Evening Slot Physics - Rotational Motion Question 164 English

Multiple Choice Options

  • A 6 kg-m2/s
  • B 8 kg-m2/s
  • C 2 kg-m2/s
  • D 3 kg-m2/s

Step-by-Step Verified Solution

Work Energy Theorem from A to B

Mgh = 1g mvB2 − 1g mvA2

2gh = vB2−vA2

2 × 10 × 10 = vB2 − 52

vB = 15m/s

Angular momentum about 0

L0 = mvr

= 20 × 10−3 × 20

L0 = 6 kg.m2/s

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