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QJEEM19Phc1c6: JEE Main 2019 Physics - Class 12 JEEM19Phc1c6 Solution: In the given circuit diagram, the currents, I 1 = – 0.3 A, I 4…

In the given circuit diagram, the currents, I1 = – 0.3 A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6, respectively, are :

JEE Main 2019 (Online) 12th January Evening Slot Physics - Current Electricity Question 250 English

Multiple Choice Options

  • A 1.1 A, – 0.4 A, 0.4 A
  • B − 0.4 A, 0.4 A, 1.1 A
  • C 0.4 A, 1.1 A, 0.4 A
  • D 1.1 A, 0.4 A, 0.4 A

Step-by-Step Verified Solution

JEE Main 2019 (Online) 12th January Evening Slot Physics - Current Electricity Question 250 English Explanation

From KCL, I3 = 0.8 − 0.4 = 0.4A

I2 = 0.4 + 0.4 + 0.3

= 1.1 A

I6 = 0.4A

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