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QJEEM19Phbe2c: JEE Main 2019 Physics - Class 11 JEEM19Phbe2c Solution: A cubical block of side 0.5 m floats on water with 30% of its…

A cubical block of side 0.5 m floats on water with 30% of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water? [Take, density of water = 103 kg/m3]

Multiple Choice Options

  • A 30.1 kg
  • B 87.5 kg
  • C 65.4 kg
  • D 46.3 kg

Step-by-Step Verified Solution

Given (50)3×30100×(1)×g=Mcubeg{\left( {50} \right)^3} \times {{30} \over {100}} \times \left( 1 \right) \times g = {M_{cube}}g     ...(i)

Let m mass should be placed

Hence (50)3 ×\times (1) ×\times g = (Mcube + m)g   …(ii)

equation (ii) – equation (i)

⇒\Rightarrow mg = (50)3 × g(1 – 0.3) = 125 × 0.7 × 103 g

⇒\Rightarrow m = 87.5 kg

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