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QJEEM19Pha71b: JEE Main 2019 Physics - Class 11 JEEM19Pha71b Solution: A man (mass = 50 kg) and his son (mass = 20 kg) are standing on …
A man (mass = 50 kg) and his son (mass = 20 kg) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of 0.70 ms–1 with respect to the man. The speed of the man with respect to the surface is :
Multiple Choice Options
- A 0.28 ms–1
- B 0.47 ms–1
- C 0.20 ms–1
- D 0.14 ms–1
Step-by-Step Verified Solution
50 V1 = 20 V2
V1 + V2 = 0.70
V1 = 0.20
V1 + V2 = 0.70
V1 = 0.20