Verified Solution • 2025–26 Session moderate

QJEEM19Pha67c: JEE Main 2019 Physics - Class 11 JEEM19Pha67c Solution: An ideal gas occupies a volume of 2m 3 at a pressure of 3 10 6…

An ideal gas occupies a volume of 2m3 at a pressure of 3 ×\times 106 Pa. The energy of the gas is :

Multiple Choice Options

  • A 6 ×\times 104 J
  • B 9 ×\times 106 J
  • C 3 ×\times 102 J
  • D 108 J

Step-by-Step Verified Solution

Energy = 12{1 \over 2} nRT = f2{f \over 2} PV

= f2{f \over 2} (3 ×\times 106) (2)

= f ×\times 3 ×\times 106

Considering gas is monoatomic i.e. f = 3

E. = 9 ×\times 106 J

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