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QJEEM19Ph880e: JEE Main 2019 Physics - Class 12 JEEM19Ph880e Solution: A conducting circular loop made of a thin wire, has area 3.5 ×…

A conducting circular loop made of a thin wire, has area 3.5 × 10−3 m2 and resistance 10 Ω. It is placed perpendicular to a time dependent magnetic field B(t) = (0.4T)sin(50πt). The field is uniform in space. Then the net charge flowing through the loop during t = 0 s and t = 10 ms is close to :

Multiple Choice Options

  • A 0.14 mC
  • B 0.7 mC
  • C 0.21 mC
  • D 0.6 mC

Step-by-Step Verified Solution

At    t  =  0 s

B(0) = 0.4 sin (0) = 0

and at t  =  10 ms

B(10) = 0.4 sin (50π×10×10-3)

= 0.4 sin (π2)

= 0.4

As q = ΔϕR

= A[B(10)−B(0)]10

= 3.5×10−3[0.4−0]10

= 0.14 mC

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