QJEEM19Ph87dd: JEE Main 2019 Physics - Class 12 JEEM19Ph87dd Solution: A He + ion is in its first excited state. Its ionization energy …

Question

Verified Solution • 2025–26 Session moderate

A He⁺ ion is in its first excited state. Its ionization energy is :-

Accepted Answer

T . E . = - (13.6) (\frac{Z^{2}}{n^{2}}) e V

z = n = 2

\Rightarrow

Ionisation energy = –T.E. = 13.6 eV

Step-by-Step Verified Solution