Verified Solution • 2025–26 Session moderate

QJEEM19Ph848d: JEE Main 2019 Physics - Class 11 JEEM19Ph848d Solution: A particle is executing simple harmonic motion (SHM) of…

A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be :

Multiple Choice Options

  • A A2
  • B A22
  • C A2
  • D A

Step-by-Step Verified Solution

Total energy of particle = 12kA2

Potential energy (v) = 12 kx2

Kinetic energy (K) = 12 kA2 − 12kx2

According to the question,

Potential energy = Kinetic energy

∴  12kx2 = 12kA2 − 12 kx2

⇒  kx2 = 12 kA2

⇒  x = ± A2

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