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QJEEM19Ph80ea: JEE Main 2019 Physics - Class 12 JEEM19Ph80ea Solution: For a uniformly charged ring of radius R, the electric field on …

For a uniformly charged ring of radius R, the electric field on its axis has the largest magnitude at a distance h from its center. Then value of h is :

Multiple Choice Options

  • A R5
  • B R2
  • C R
  • D R2

Step-by-Step Verified Solution

JEE Main 2019 (Online) 9th January Morning Slot Physics - Electrostatics Question 187 English Explanation

Electric field on the axis of the ring,

E=KQh(R2+h2)32

For maximum electric field,

dEdh=0

⇒   h=R2

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