Verified Solution • 2025–26 Session
moderate
QJEEM19Ph79fe: JEE Main 2019 Physics - Class 11 JEEM19Ph79fe Solution: A 25 × 10 –3 m 3 volume cylinder is filled with 1 mol of O 2…
A 25 × 10–3 m3 volume cylinder is filled with 1 mol of O2 gas at room temperature (300K). The molecular diameter of O2, and its root mean square speed, are found to be 0.3 nm, and 200 m/s, respectively. What is the average collision rate (per second) for an O2 molecule ?
Multiple Choice Options
- A ~1013
- B ~1012
- C ~1011
- D ~1010
Step-by-Step Verified Solution
V = 25 × 10–3 m3, N = 1 mole of O2
T = 300 K
Vrms = 200 m/s
Average time {1 \over \tau } = {{ < V > } \over \lambda } = 200\,.N\pi {r^2}.\sqrt 2
Average no. of collision
T = 300 K
Vrms = 200 m/s
Average time {1 \over \tau } = {{ < V > } \over \lambda } = 200\,.N\pi {r^2}.\sqrt 2
Average no. of collision