Verified Solution • 2025–26 Session moderate

QJEEM19Ph7155: JEE Main 2019 Physics - Class 11 JEEM19Ph7155 Solution: A thin smooth rod of length L and mass M is rotating freely…

A thin smooth rod of length L and mass M is rotating freely with angular speed ω0 about an axis perpendicular to the rod and passing through its center. Two beads of mass m and negligible size are at the center of the rod initially. The beads are free to slide along the rod. The angular speed of the system , when the beads reach the opposite ends of the rod, will be :-

Multiple Choice Options

  • A Mω0M+3m
  • B Mω0M+m
  • C Mω0M+6m
  • D Mω0M+2m

Step-by-Step Verified Solution

Initial angular momentum = Final Angular Momentum

ML212ω0=(ML212+2mL24)ω

⇒ω=Mω0M+6m

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