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QJEEM19Ph674d: JEE Main 2019 Physics - Class 11 JEEM19Ph674d Solution: A solid sphere and solid cylinder of identical radii approach…

A solid sphere and solid cylinder of identical radii approach an incline with the same linear velocity (see figure). Both roll without slipping all throughout. The two climb maximum heights hsph and hcyl on the incline. The ratio hsph/hcyl is given by :- JEE Main 2019 (Online) 8th April Evening Slot Physics - Rotational Motion Question 159 English

Multiple Choice Options

  • A 1
  • B 14/15
  • C `4/5
  • D `2/5

Step-by-Step Verified Solution

For solid sphere
12mv2+12.25mR2.v2R2=mghsph

For solid cylinder
12mv2+12.12mR2.v2R2=mghcyl

⇒hsphhcyl=7/53/2=1415

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