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QJEEM19Ph66ab: JEE Main 2019 Physics - Class 11 JEEM19Ph66ab Solution: The elastic limit of brass is 379 MPa. What should be the…

The elastic limit of brass is 379 MPa. What should be the minimum diameter of a brass rod if it is to support a 400 N load without exceeding its elastic limit?

Multiple Choice Options

A 1.16 mm
B 1.36 mm
C 1.00 mm
D 0.90 mm

Step-by-Step Verified Solution

\frac{400}{\frac{π}{4} d^{2}} = 379 \times 10^{6}

d^{2} = \frac{4 \times 400 \times 10^{- 6}}{π \times 379} = 0.336 \times 10^{- 6} \times 4

d = 2 \sqrt{0.336} \times 10^{- 3} M ≃ 1.16 m m

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