Verified Solution • 2025–26 Session moderate

QJEEM19Ph60a4: JEE Main 2019 Physics - Class 11 JEEM19Ph60a4 Solution: A sample of an ideal gas is taken through the cyclic process…

A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the internal energy of the gas along the path ca is –180 J. The gas absorbs 250 J of heat along the path ab and 60 J along the path bc. The work done by the gas along the path abc is: JEE Main 2019 (Online) 12th April Morning Slot Physics - Heat and Thermodynamics Question 304 English

Multiple Choice Options

  • A 120 J
  • B 130 J
  • C 100 J
  • D 140 J

Step-by-Step Verified Solution

For the process (c – a), ΔUca = – 180 J

For process (b – c) → Isochoric (Wbc = 0)

∴ΔU = 60 J

Heat absorbs along (a – b), Qab = 250 J

Also ∴Δ Ucycle = 0

∴Δ Uab = 120 J

So Wa → b = 130 J

Total work done from (a → b → c)

= Wab + Wbc = 130 J

Related Learning Resources & Exam Preparation