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QJEEM19Ph60a4: JEE Main 2019 Physics - Class 11 JEEM19Ph60a4 Solution: A sample of an ideal gas is taken through the cyclic process…
A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the internal energy of the gas along the path ca is –180 J. The gas absorbs 250 J of heat along the path ab and 60 J along the path bc. The work done by the gas along the path abc is:
Multiple Choice Options
- A 120 J
- B 130 J
- C 100 J
- D 140 J
Step-by-Step Verified Solution
For the process (c – a), Uca = – 180 J
For process (b – c) Isochoric (Wbc = 0)
U = 60 J
Heat absorbs along (a – b), Qab = 250 J
Also Ucycle = 0
Uab = 120 J
So Wa b = 130 J
Total work done from (a b c)
= Wab + Wbc = 130 J
For process (b – c)
Heat absorbs along (a – b), Qab = 250 J
Also
So Wa
Total work done from (a
= Wab + Wbc = 130 J