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QJEEM19Ph5c09: JEE Main 2019 Physics - Class 12 JEEM19Ph5c09 Solution: The self induced emf of a coil is 25 volts. When the current in …

The self induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is -

Multiple Choice Options

  • A 740 J
  • B 637.5 J
  • C 540 J
  • D 437.5 J

Step-by-Step Verified Solution

Ldidt=25

L×151=25

L=53H

ΔE=12×53×(252−102)

=56×525=437.5 J

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