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QJEEM19Ph5b6e: JEE Main 2019 Physics - Class 12 JEEM19Ph5b6e Solution: A rigid square loop of side 'a' and carrying current I 2 is…
A rigid square loop of side 'a' and carrying current I2 is lying on a horizontal surface near a long current I1 carrying wire in the same plane as shown in figure. The net force on the loop due to wire will be : 
Multiple Choice Options
- A Repulsive and equal to μ0I1I2/4π
- B Attractive and equal to μ0I1I2/3π
- C Repulsive and equal to μ0I1I2/2π
- D Zero
Step-by-Step Verified Solution
F3 & F4 cancel each other.
Force on PQ will be F1 = I2B1 a
=
=
Force on RS will be F2 = I2 B2 a
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Net force = F1 – F2 =
Force on PQ will be F1 = I2B1 a
=
=
Force on RS will be F2 = I2 B2 a
=
Net force = F1 – F2 =