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QJEEM19Ph5903: JEE Main 2019 Physics - Class 12 JEEM19Ph5903 Solution: A parallel plate capacitor has 1μF capacitance. One of its two…

A parallel plate capacitor has 1μF capacitance. One of its two plates is given +2μC charge and the other plate, +4μC charge. The potential difference developed across the capacitor is:-

Multiple Choice Options

  • A 1V
  • B 5V
  • C 2V
  • D 3V

Step-by-Step Verified Solution

JEE Main 2019 (Online) 8th April Evening Slot Physics - Capacitor Question 114 English Explanation Charges at inner plates are 1 μ\mu C and –1 μ\mu C.

∴\therefore Potential difference across capacitor
= qc=1μC1μF=1×10−6C1×10−6Farad=1V{q \over c} = {{1\mu C} \over {1\mu F}} = {{1 \times {{10}^{ - 6}}C} \over {1 \times {{10}^{ - 6}}Farad}} = 1V

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