Verified Solution • 2025–26 Session moderate

QJEEM19Ph52ea: JEE Main 2019 Physics - Class 11 JEEM19Ph52ea Solution: A liquid of density is coming out of a hose pipe of radius a…

A liquid of density ρ\rho is coming out of a hose pipe of radius a with horizontal speed υ\upsilon and hits a mesh. 50% of the liquid passes through the mesh unaffected. 25% looses all of its momentum and 25% comes back with the same speed. The resultant pressure on the mesh will be :

Multiple Choice Options

  • A 34ρv2{3 \over 4}\rho {v^2}
  • B 14ρv2{1 \over 4}\rho {v^2}
  • C 12ρv2{1 \over 2}\rho {v^2}
  • D ρv2\rho {v^2}

Step-by-Step Verified Solution

Momentum per second carried by liquid per second is ρ\rho av2

net force due to reflected liquid = 2 ×\times [14ρav2]\left[ {{1 \over 4}\rho a{v^2}} \right]

net force due to stopped liquid = 14ρav2{{1 \over 4}\rho a{v^2}}

Total force = 34ρav2{{3 \over 4}\rho a{v^2}}

net pressure = 34ρv2{{3 \over 4}\rho {v^2}}

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