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QJEEM19Ph4fe5: JEE Main 2019 Physics - Class 12 JEEM19Ph4fe5 Solution: The resistive network shown below is connected to a D.C. source …

The resistive network shown below is connected to a D.C. source of 16 V. The power consumed by the network is 4 Watt. The value of R is: JEE Main 2019 (Online) 12th April Morning Slot Physics - Current Electricity Question 233 English

Multiple Choice Options

  • A 16 Ω
  • B 1 Ω
  • C 8 Ω
  • D 6 Ω

Step-by-Step Verified Solution

Req = 2R + R + 4R + R = 8R

P=v2Req⇒16×168R=4watt

16×164×8=R⇒R=8Ω

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