Verified Solution • 2025–26 Session moderate

QJEEM19Ph40f1: JEE Main 2019 Physics - Class 11 JEEM19Ph40f1 Solution: Two kg of a monoatomic gas is at a pressure of 4 10 4 N/m 2 .…

Two kg of a monoatomic gas is at a pressure of 4 ×\times 104 N/m2. The density of the gas is 8 kg/m3. What is the order of energy of the gas due to its thermal motion ?

Multiple Choice Options

  • A 104 J
  • B 103 J
  • C 105 J
  • D 106 J

Step-by-Step Verified Solution

Thermal energy of N molecule

= N (32kT)\left( {{3 \over 2}kT} \right)

= NNA32{N \over {{N_A}}}{3 \over 2} RT

= 32{3 \over 2} (nRT)

= 32{3 \over 2} PV

= 32{3 \over 2} P (m8)\left( {{m \over 8}} \right)

= 32{3 \over 2} ×\times 4 ×\times 104 ×\times 28{2 \over 8}

= 1.5 ×\times 104

order will 104

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