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QJEEM19Ph3857: JEE Main 2019 Physics - Class 12 JEEM19Ph3857 Solution: A thin convex lens L (refractive index = 1.5) is placed on a…

A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA = 18 cm, its real inverted image is formed at A itself, as shown in figure. When a liquid of refractive index μ1 is put between the lens and the mirror, The pin has to be moved to A', such that OA' = 27 cm, to get its inverted real image at A' itself. The value of μ1 will be :- JEE Main 2019 (Online) 9th April Evening Slot Physics - Geometrical Optics Question 164 English

Multiple Choice Options

  • A sqrt3sqrt3
  • B `3/2
  • C 2
  • D `4/3

Step-by-Step Verified Solution

For image to form at object itself, says must retrace their path back to object. Hence must incident on mirror normally.

Case 1: Object will be at focus of lens
1f=(μ−1)(1R−1−R)=1−18 ⇒ R = 18 cm

Case 2: Retraction at 1st surface:
1−27−1.5V1=1−1.5R    ... (i)

2nd retraction:
1.5V1−μ∞=15−u−R   ...(ii)

From (i) and (ii)
μ=43

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