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QJEEM19Ph2a1f: JEE Main 2019 Physics - Class 12 JEEM19Ph2a1f Solution: In a line of sight radio communication, a distance of about 50…

In a line of sight radio communication, a distance of about 50 km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70m, then the minimum height of the transmitting antenna should be :
(Radius of the Earth = 6.4 × 106 m).

Multiple Choice Options

  • A 40 m
  • B 20 m
  • C 51 m
  • D 32 m

Step-by-Step Verified Solution

Range = 2RhT+2RhR\sqrt {2R{h_T}} + \sqrt {2R{h_R}}

50×103=2×6400×103×hT+2×6400×103×7050 \times {10^3} = \sqrt {2 \times 6400 \times {{10}^3} \times {h_T}} + \sqrt {2 \times 6400 \times {{10}^3} \times 70}

By solving hT = 32 m.

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