Verified Solution • 2025–26 Session moderate

QJEEM19Ph29f7: JEE Main 2019 Physics - Class 12 JEEM19Ph29f7 Solution: The figure shows a square loop L of side 5 cm which is…

The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a constant speed of 1 cm s-1. At some instant, a part of L is in a uniform magnetic field of 1 T, perpendicular to the plane of the loop. If the resistance of L is 1.7 Ω\Omega , the current in the loop at that instant will be close to : JEE Main 2019 (Online) 12th April Morning Slot Physics - Electromagnetic Induction Question 94 English

Multiple Choice Options

  • A 115 μ\mu A
  • B 170 μ\mu A
  • C 60 μ\mu A
  • D 150 μ\mu A

Step-by-Step Verified Solution

Since it is a balanced wheatstone bridge, its equivalent resistance = 43Ω{4 \over 3}\Omega

ε=Bℓv=5×10−4V\varepsilon = B\ell v = 5 \times {10^{ - 4}}V

So total resistance
R=43+1.7≈3ΩR = {4 \over 3} + 1.7 \approx 3\Omega

∴i=εR≈166 μA≈170 μA\therefore i = {\varepsilon \over R} \approx 166\,\mu A \approx 170\,\mu A

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring