QJEEM19Ph29e8: JEE Main 2019 Physics - Class 11 JEEM19Ph29e8 Solution: A simple harmonic motion is represented by : y = 5 (sin 3 π t + …

Question

Verified Solution • 2025–26 Session moderate

A simple harmonic motion is represented by :

y = 5 (sin 3

π

t +

\sqrt{3}

cos 3

π

t) cm

The amplitude and time period of the motion are :

Accepted Answer

y = 5[sin(3

π

t) +

\sqrt{3}

cos(3

π

t)]

= 10sin

(3 π t + \frac{π}{3})

Amplitude = 10 cm

T =

\frac{2 π}{w}

=

\frac{2 π}{3 π}

=

\frac{2}{3}

sec

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