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QJEEM19Ph28a6: JEE Main 2019 Physics - Class 12 JEEM19Ph28a6 Solution: A parallel plate capacitor with plates of area 1 m 2 each, are…

A parallel plate capacitor with plates of area 1 m2 each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge on each plate is :

(Take ε0 = 8.85 × 10−12 C2N−m2)

Multiple Choice Options

  • A 9.85 × 10–10 C
  • B 8.85 × 10–10 C
  • C 6.85 × 10–10 C
  • D 7.85 × 10–10 C

Step-by-Step Verified Solution

E=σ∈0=QA∈0

Q = AE∈0

Q = (1) (100) (8.85 × 10−12)

Q = 8.85 × 10−10C

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