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QJEEM19Ph276f: JEE Main 2019 Physics - Class 12 JEEM19Ph276f Solution: Voltage rating of a parallel plate capacitor is 500V. Its…

Voltage rating of a parallel plate capacitor is 500V. Its dielectric can withstand a maximum electric field of 106 V/m. The plate area is 10–4 m2. What is the dielectric constant is the capacitance is 15 pF? (given ε0 = 8.86 × 10–12 C2/Nm2)

Multiple Choice Options

  • A 8.5
  • B 4.5
  • C 3.8
  • D 6.2

Step-by-Step Verified Solution

A = 10–4 m2

Emax = 106 V/m

C = 15 μF

C=kε0Ad;Cdε0A=k

k=15×10−12×500×10−68.86×10−12×104

= 15×58.86=8.465

k ≈ 8.5

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