QJEEM19Ph18b9: JEE Main 2019 Physics - Class 12 JEEM19Ph18b9 Solution: In a Young's double slit experiment, the slits are placed 0.320 …

Question

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In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength

\lambda

= 500 nm is incident on the slits. The total number of bright fringes that are observed in the angular range

-

30^o

\le

\theta

\le

30^o is :

Accepted Answer

We know, path difference,

d sin

\theta

= n

\lambda

here n = no of bright fringer in the angle

here given

d = 0.32

\times

10^-3 m

\lambda

= 500

\times

10^{$-$ 9} m

\therefore

0.32

\times

10^{$-$ 3} sin30^o = n

\times

500

\times

10^{$-$ 9}

\Rightarrow

n = 320

Total number of maxima in the range

-

30^o

\theta

\le

30^o is = 320

\times

2 + 1 = 641

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