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QJEEM19Ph1785: JEE Main 2019 Physics - Class 12 JEEM19Ph1785 Solution: Four equal point charges Q each are placed in the xy plane at…

Four equal point charges Q each are placed in the xy plane at (0, 2), (4, 2), (4, –2) and (0, –2). The work required to put a fifth charge Q at the origin of the coordinate system will be -

Multiple Choice Options

  • A Q24πε0{{{Q_2}} \over {4\pi {\varepsilon _0}}}
  • B Q222πε0{{{Q^2}} \over {2\sqrt 2 \pi {\varepsilon _0}}}
  • C Q24πε0(1+13){{{Q_2}} \over {4\pi {\varepsilon _0}}}\left( {1 + {1 \over {\sqrt 3 }}} \right)
  • D Q24πε0(1+15){{{Q_2}} \over {4\pi {\varepsilon _0}}}\left( {1 + {1 \over {\sqrt 5 }}} \right)

Step-by-Step Verified Solution

JEE Main 2019 (Online) 10th January Evening Slot Physics - Electrostatics Question 182 English Explanation

Potential at origin = KQ2+KQ2+KQ20+KQ20{{KQ} \over 2} + {{KQ} \over 2} + {{KQ} \over {\sqrt {20} }} + {{KQ} \over {\sqrt {20} }}

(Potential at ∞\infty = 0)

= KQ (1+15)\left( {1 + {1 \over {\sqrt 5 }}} \right)

∴\therefore   Work required to put a fifth charge Q

at origin is equal to Q24πε0(1+15){{{Q^2}} \over {4\pi {\varepsilon _0}}}\left( {1 + {1 \over {\sqrt 5 }}} \right)

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