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QJEEM19Ph0ef9: JEE Main 2019 Physics - Class 11 JEEM19Ph0ef9 Solution: A body of mass m 1 moving with an unknown velocity of v 1 i ∧ , …

A body of mass m1 moving with an unknown velocity of v1i∧, undergoes a collinear collision with a body of mass m2 moving with a velocity v2i∧ . After collision, m1 and m2 move with velocities of v3i∧ and v4i∧ , respectively. If m2 = 0.5 m1 and v3 = 0.5 v1, then v1 is :-

Multiple Choice Options

  • A v4−v22
  • B v4−v24
  • C v4−v2
  • D v4+v2

Step-by-Step Verified Solution

Applying linear momentum conservation

m1v1i^+m2v2i^=m1v3i^+m2v4i^

m1v1 + 0.5 m1v2 = m1(0.5 v1) + 0.5 m1v4

0.5 m1v1 = 0.5 m1(v4 - v2)

v1 = v4 - v2

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