Verified Solution • 2025–26 Session
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QJEEM19Ph0ef9: JEE Main 2019 Physics - Class 11 JEEM19Ph0ef9 Solution: A body of mass m 1 moving with an unknown velocity of v 1 i ∧ , …
A body of mass m1 moving with an unknown velocity of , undergoes a collinear collision with a body of mass m2 moving with a velocity . After collision, m1 and m2 move with velocities of and , respectively. If m2 = 0.5 m1 and v3 = 0.5 v1, then v1 is :-
Multiple Choice Options
- A v4−v22
- B v4−v24
- C v4−v2
- D v4+v2
Step-by-Step Verified Solution
Applying linear momentum conservation
m1v1 + 0.5 m1v2 = m1(0.5 v1) + 0.5 m1v4
0.5 m1v1 = 0.5 m1(v4 - v2)
v1 = v4 - v2
m1v1 + 0.5 m1v2 = m1(0.5 v1) + 0.5 m1v4
0.5 m1v1 = 0.5 m1(v4 - v2)
v1 = v4 - v2