QJEEM19Mad971: JEE Main 2019 Mathematics - Class 12 JEEM19Mad971 Solution: An urn contains 5 red and 2 green balls. A ball is drawn at…

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QJEEM19Mad971: JEE Main 2019 Mathematics - Class 12 JEEM19Mad971 Solution: An urn contains 5 red and 2 green balls. A ball is drawn at…

An urn contains 5 red and 2 green balls. A ball is drawn at random from the urn. If the drawn ball is green, then a red ball is added to the urn and if the drawn ball is red, then a green ball is added to the urn; the original ball is not returned to the urn. Now, a second ball is drawn at random from it. The probability that the second ball is red, is :

Multiple Choice Options

A 2149
B 2749
C 2649
D 3249

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Accepted Answer

5 Red and 2 green balls

P(one red ball) =

\frac{5}{7}

P(one green ball) =

\frac{2}{7}

Case I :

If drawn ball is green than a red ball is added

(\begin{matrix} 6 Re d \\ 1 G r e e n \end{matrix})

P (red ball) =

\frac{6}{7}

Case II :

If drawn ball is red than a green ball is added

(\begin{matrix} 4 Re d \\ 3 G r e e n \end{matrix})

P (red ball) =

\frac{4}{7}

P (2^nd red ball) =

\frac{5}{7}

\times \frac{4}{7} + \frac{2}{7} \times \frac{6}{7}

=

\frac{32}{49}

QJEEM19Mad971: JEE Main 2019 Mathematics - Class 12 JEEM19Mad971 Solution: An urn contains 5 red and 2 green balls. A ball is drawn at…

Multiple Choice Options

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