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QJEEM19Mad572: JEE Main 2019 Mathematics - Class 12 JEEM19Mad572 Solution: The area (in sq. units) of the region bounded by the curve x 2…

The area (in sq. units) of the region bounded by the curve x2 = 4y and the straight line x = 4y – 2 is :

Multiple Choice Options

  • A 34
  • B 54
  • C 78
  • D 98

Step-by-Step Verified Solution

JEE Main 2019 (Online) 11th January Morning Slot Mathematics - Area Under The Curves Question 118 English Explanation
x = 4y − 2 & x2 = 4y

⇒  x2 = x + 2 ⇒ x2 − x − 2 = 0

x = 2, − 1

So,   ∫−12(x+24−x24)dx=98

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