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QJEEM19Mad08f: JEE Main 2019 Physics - Class 11 JEEM19Mad08f Solution: Let A (3, 0, –1), B(2, 10, 6) and C(1, 2, 1) be the vertices of …

Let A (3, 0, –1), B(2, 10, 6) and C(1, 2, 1) be the vertices of a triangle and M be the midpoint of AC. If G divides BM in the ratio, 2 : 1, then cos (∠GOA) (O being the origin) is equal to :

Multiple Choice Options

  • A 115
  • B 1610
  • C 130
  • D 1215

Step-by-Step Verified Solution

G is the centroid of ΔABC

JEE Main 2019 (Online) 10th April Morning Slot Mathematics - Vector Algebra Question 185 English Explanation

OG=4+16+4, OA = 9+1

AG=1+16+9

cos⁡θ=24+10−2622410

⇒828×3×2×5

⇒4415=115

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