Verified Solution • 2025–26 Session moderate

QJEEM19Mabb7c: JEE Main 2019 Mathematics - Class 11 JEEM19Mabb7c Solution: Let a, b and c be the 7 th , 11 th and 13 th terms respectively …

Let a, b and c be the 7th, 11th and 13th terms respectively of a non-constant A.P. If these are also three consecutive terms of a G.P., then ac equal to :

Multiple Choice Options

  • A 2
  • B 12
  • C 713
  • D 4

Step-by-Step Verified Solution

T7 = A + 6d = a; T11 = A + 10d = b; T13 = A + 12d = c

Now a, b, c are in G.P.

∴  b2 = ac

⇒  (A + 10d)2 = (A + 6d) (A + 12d)

⇒  A2 + 100d2 + 20Ad = A2 + 18Ad + 72d2

⇒  A + 14d = 0, A = − 14d

ac=A+6dA+12d=−8d−2d=4

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