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QJEEM19Maa73a: JEE Main 2019 Mathematics - Class 11 JEEM19Maa73a Solution: Let S n denote the sum of the first n terms of an A.P. If S 4 = …

Let Sn denote the sum of the first n terms of an A.P. If S4 = 16 and S6= – 48, then S10 is equal to :

Multiple Choice Options

  • A -320
  • B -380
  • C -460
  • D -210

Step-by-Step Verified Solution

S4 = 42(2a+3d)=16{4 \over 2}\left( {2a + 3d} \right) = 16

⇒2a+3d=8\Rightarrow 2a + 3d = 8

S4 = 62(2a+5d)=−48{6 \over 2}\left( {2a + 5d} \right) = -48

⇒2a+5d=−16\Rightarrow 2a + 5d = -16

∴\therefore d = -12 and a = 22, Now S10 = 102(44−108)=−320{{10} \over 2}\left( {44 - 108} \right) = - 320

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