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QJEEM19Maa654: JEE Main 2019 Mathematics - Class 12 JEEM19Maa654 Solution: If ƒ(x) is a non-zero polynomial of degree four, having local…

If ƒ(x) is a non-zero polynomial of degree four, having local extreme points at x = –1, 0, 1; then the set
S = {x ∈\in R : ƒ(x) = ƒ(0)}
Contains exactly :

Multiple Choice Options

  • A four rational numbers.
  • B four irrational numbers.
  • C two irrational and one rational number.
  • D two irrational and two rational numbes.

Step-by-Step Verified Solution

Local extreme points of f(x) is at x = –1, 0, 1.

∴\therefore f'(x) = 0 has three solutions x = –1, 0, 1.

∴\therefore f'(x) = k(x + 1)x(x - 1)

∫f′(x)dx=∫k(x+1)x(x−1)dx\int {f'(x)dx} = \int {k(x + 1)x(x - 1)dx}

f(x) = k[x44−x22]+Ck\left[ {{{{x^4}} \over 4} - {{{x^2}} \over 2}} \right] + C

Also given that

ƒ(x) = ƒ(0)

∴\therefore k[x44−x22]+Ck\left[ {{{{x^4}} \over 4} - {{{x^2}} \over 2}} \right] + C = C

⇒\Rightarrow x22(x22−1){{{x^2}} \over 2}\left( {{{{x^2}} \over 2} - 1} \right) = 0

⇒\Rightarrow x = 0, −2- \sqrt 2 , 2\sqrt 2

∴\therefore x has two irrational and one rational value.

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