Verified Solution • 2025–26 Session moderate

QJEEM19Maa33d: JEE Main 2019 Mathematics - Class 11 JEEM19Maa33d Solution: If the area of the triangle whose one vertex is at the vertex…

If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x – a2) = 0 and the othertwo vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of 'a' is :

Multiple Choice Options

  • A 555\sqrt 5
  • B (10)2/3{\left( {10} \right)^{2/3}}
  • C 5(21/3)5\left( {{2^{1/3}}} \right)
  • D 5

Step-by-Step Verified Solution

Vertex is (a2, 0)

y2 == −- (x −- a2) and x == 0 ⇒\Rightarrow (0, ±\pm 2a)

Area of triangle is =12.= {1 \over 2}. 4a.(a2) = 250

⇒\Rightarrow   a3 = 125 or a = 5

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