Verified Solution • 2025–26 Session moderate

QJEEM19Ma9cb8: JEE Main 2019 Mathematics - Class 11 JEEM19Ma9cb8 Solution: If the system of linear equations x – 2y + kz = 1 2x + y + z =…

If the system of linear equations

x – 2y + kz = 1
2x + y + z = 2
3x – y – kz = 3

has a solution (x,y,z), z ≠ 0, then (x,y) lies on the straight line whose equation is :

Multiple Choice Options

  • A 4x – 3y – 4 = 0
  • B 3x – 4y – 1 = 0
  • C 4x – 3y – 1 = 0
  • D 3x – 4y – 4 = 0

Step-by-Step Verified Solution

x – 2y + kz = 1 ......(1)

2x + y + z = 2 .........(2)

3x – y – kz = 3 ........(3)

for locus of (x, y) add equation (1) + (3)

4x – 3y = 4

⇒ 4x – 3y - 4 = 0

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