QJEEM19Ma9bbe: JEE Main 2019 Mathematics - Class 11 JEEM19Ma9bbe Solution: If  0 x < ,  then the number of values of x for…

Question

Verified Solution • 2025–26 Session moderate

If 0

\le

x <

{\pi \over 2}

, then the number of values of x for which sin x

-

sin 2x + sin 3x = 0, is :

Accepted Answer

sin x

-

sin 2x + sin 3x = 0

x \in \left[ {0,{\pi \over 2}} \right)

\Rightarrow

(sin3x + sinx)

-

sin2x = 0

\Rightarrow

2sin2x.cos2x

-

sin2x = 0

\Rightarrow

sin2x (2cosx

-

1) = 0

sin 2x = 0

x = 0

and cos x =

{1 \over 2}

and x =

{\pi \over 3}

two solutions

QJEEM19Ma9bbe: JEE Main 2019 Mathematics - Class 11 JEEM19Ma9bbe Solution: If&nbsp;&nbsp;0 x < , &nbsp;then the number of values of x for…