Verified Solution • 2025–26 Session moderate

QJEEM19Ma90ab: JEE Main 2019 Mathematics - Class 11 JEEM19Ma90ab Solution: If the function ƒ : R – {1, –1} A defined by ƒ(x) = , is…

If the function ƒ : R – {1, –1} →\to A defined by
ƒ(x) = x21−x2{{{x^2}} \over {1 - {x^2}}} , is surjective, then A is equal to

Multiple Choice Options

  • A R – (–1, 0)
  • B R – {–1}
  • C R – [–1, 0)
  • D [0, ∞\infty )

Step-by-Step Verified Solution

Let ƒ(x) = x21−x2{{{x^2}} \over {1 - {x^2}}} = y

⇒\Rightarrow y(1−x2)=x2y\left( {1 - {x^2}} \right) = {x^2}

⇒\Rightarrow x2=y1+y{x^2} = {y \over {1 + y}}

As x2{x^2} is always ≥\ge 0.

∴\therefore y1+y{y \over {1 + y}} ≥\ge 0

y ∈\in (−∞,−1)∪[0,∞)\left( { - \infty , - 1} \right) \cup \left[ {0,\left. \infty \right)} \right.

For surjective function co-domain = Range

∴\therefore A is R – [–1, 0).

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