QJEEM19Ma775f: JEE Main 2019 Mathematics - Class 12 JEEM19Ma775f Solution: Let   f ( x ) = { max {

Question

Verified Solution • 2025–26 Session moderate

Let

f (x) = {\begin{matrix} max {| x |, x^{2}} & | x | \leq 2 \\ 8 - 2 | x | & 2 < | x | \leq 4 \end{matrix}

Let S be the set of points in the interval (– 4, 4) at which f is not differentiable. Then S

Accepted Answer

f (x) = {\begin{matrix} 8 + 2 x, & - 4 \leq x \leq - 2 \\ x^{2}, & - 2 \leq x \leq - 1 \\ | x |, & - 1 < x < 1 \\ x^{2}, & 1 \leq x \leq 2 \\ 8 - 2 x, & 2 < x \leq 4 \end{matrix}

f(x) is not differentiable at

x =

{- 2, - 1, 0, 1, 2}

\Rightarrow

S = {

-

2,

-

1, 0, 1, 2}

QJEEM19Ma775f: JEE Main 2019 Mathematics - Class 12 JEEM19Ma775f Solution: Let&nbsp;&nbsp; f ( x ) = { max {