Verified Solution • 2025–26 Session moderate

QJEEM19Ma729b: JEE Main 2019 Mathematics - Class 11 JEEM19Ma729b Solution: Which one of the following statements is not a tautology?

Which one of the following statements is not a tautology?

Multiple Choice Options

  • A (p ∧\wedge q) →\to (~ p) ∨\vee q
  • B (p ∧\wedge q) →\to p
  • C ( p ∨\vee q) →\to ( p ∨\vee (~q))
  • D p →\to ( p ∨\vee q)

Step-by-Step Verified Solution

Here you have to check all the options.

We know, p →\to q = ∼\sim p ∨\vee q

(A) (p ∧\wedge q) →\to (~ p) ∨\vee q

= ∼\sim (p ∧\wedge q) ∨\vee ((~ p) ∨\vee q)

= ( ∼\sim p ∨\vee ∼\sim q) ∨\vee ((~ p) ∨\vee q)

= ∼\sim p ∨\vee (q ∨\vee ∼\sim q)

= ∼\sim p ∨\vee t

[(q ∨\vee ∼\sim q) = t (tautology)]

= t

(B) (p ∧\wedge q) →\to p

= ∼\sim (p ∧\wedge q) ∨\vee p

= ∼\sim p ∨\vee ∼\sim q ∨\vee p

= t ∨\vee ∼\sim q

= t

(C) ( p ∨\vee q) →\to ( p ∨\vee (~q))

= ∼\sim ( p ∨\vee q) ∨\vee ( p ∨\vee (~q))

= ( ∼\sim p ∧\wedge ∼\sim q) ∨\vee ( p ∨\vee (~q))

= ∼\sim q ∧\wedge (p ∨\vee ∼\sim p)

= ∼\sim q ∧\wedge t

= ∼\sim q (not tautology)

(D) p →\to ( p ∨\vee q)

= ∼\sim p ∨\vee ( p ∨\vee q)

= t ∨\vee q

= t

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