QJEEM19Ma5881: JEE Main 2019 Physics - Class 11 JEEM19Ma5881 Solution: The distance of the point having position vector from the…

Question

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The distance of the point having position vector

- \widehat i + 2\widehat j + 6\widehat k

from the straight line passing through the point (2, 3, – 4) and parallel to the vector,

6\widehat i + 3\widehat j - 4\widehat k

is :

Accepted Answer

AD = \left| {{{\overrightarrow {AP} .\overrightarrow n } \over {\left| {\overrightarrow n } \right|}}} \right| = \sqrt {61}

\Rightarrow PD = \sqrt {A{P^2} - A{D^2}}

= \sqrt {110 - 61}

= 7

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