Verified Solution • 2025–26 Session moderate

QJEEM19Ma4684: JEE Main 2019 Mathematics - Class 12 JEEM19Ma4684 Solution: Four persons can hit a target correctly with probabilities , ,…

Four persons can hit a target correctly with probabilities 12{1 \over 2} , 13{1 \over 3} , 14{1 \over 4} and 18{1 \over 8} respectively. if all hit at the target independently, then the probability that the target would be hit, is :

Multiple Choice Options

  • A 2532{{25} \over {32}}
  • B 25192{{25} \over {192}}
  • C 1192{{1} \over {192}}
  • D 732{{7} \over {32}}

Step-by-Step Verified Solution

Let four persons are A, B, C and D.

Probablity of hitting a target by them,

P(A) = 12{1 \over 2}

P(B) = 13{1 \over 3}

P(C) = 14{1 \over 4}

P(D) = 18{1 \over 8}

Probablity of hitting target atleast once = 1 - Probablity of not hitting by anybody

P(Hit) = 1 - P(A‾∩B‾∩C‾∩D‾)P\left( {\overline A \cap \overline B \cap \overline C \cap \overline D } \right)

= 1 - P(A‾).P(B‾).P(C‾).P(D‾)P\left( {\overline A } \right).P\left( {\overline B } \right).P\left( {\overline C } \right).P\left( {\overline D } \right)

= 1 - 12.23.34.78{1 \over 2}.{2 \over 3}.{3 \over 4}.{7 \over 8}

= 2532{{25} \over {32}}

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